For all positive integers n, the symbol n! denotes the product of the first n positive
integers.
Example: 4! = 4x3x2x1=24
Find the value of n for which (3!)(5!)(7!) = n!
2007-11-29 07:23:45 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
anither question
You are given a square, each of whose sides measure x meters.
If the corners of the square are cut off so that a regular octagon remains, how long is each
side of the resulting octagon in terms of x?
2007-11-29 07:44:16 · update #1
Wel,, lets first figure out the factorials...
3! = 3*2*1 = 6
5! = 5*4*3*2*1 = 120
7! = 7*6*5*4*3*2*1 = 5040...
6*120*5040 = 3628800
3628800 is equal to 10!, therefore, n! = 10!
I had a question just like this in Mathcounts..
2007-11-29 07:28:49 · answer #1 · answered by Anonymous · 0⤊ 1⤋
3!=6
5!=120
7!=5040
(3!)(5!)(7!)=3628800
If you divide it up into its factors (ohhh, geez), then you will find some sort of answer. But since it is greater than seven factorial, as you are multiplying this number by 3, 5, and 7 factorial, factor out 7!.
3628800/7!=720. This means that the remaining integers have to be factors of 720.
720 = 8*90
720 = 8*9*10.
Therefore, (3!)(5!)(7!)=10!
2007-11-29 07:32:41 · answer #2 · answered by renomitsu 3 · 0⤊ 0⤋
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2016-10-18 08:51:35 · answer #3 · answered by Anonymous · 0⤊ 0⤋
3!=3(2)
5!=5(4)(3)(2)
7!=7(6)(5)(4)(3)(2)
the 5 from 5! pairs with the 2 in 3! making 10
the 3 from 5! pairs with the 3 in 3! making 9
the 4 from 5! pairs with the 2 in 3! making 8
the 7! stays the same=> 10(9)(8)(7!) =10!
2007-11-29 07:46:50 · answer #4 · answered by Optimist 2 · 0⤊ 0⤋
6*120*5040=3628800=10!
n=10
2007-11-29 07:32:29 · answer #5 · answered by iyiogrenci 6 · 0⤊ 0⤋
3!=3x2x1=6
5!=5x4x3x2x1=120
7!=7x6x5x4x3x2x1=5040
n!=6x120x5040
n!=3628800 --> n!=10
2007-11-29 07:42:47 · answer #6 · answered by $$$$$$$$$$$$$ 2 · 0⤊ 0⤋
answer is 10!, theres no formula for getting this answer, it preety much a guess and check
2007-11-29 07:30:12 · answer #7 · answered by P 3 · 0⤊ 0⤋