I've come to the conclusion that if a rotating black was rotating at once per second then its maximum dia..must not exceed 59271.5454545455 miles. otherwise its suface at the equator would be traveling faster than light.
Is this true..
2007-11-29 07:04:18 · 12 answers · asked by emc.squared 1 in Science & Mathematics ➔ Astronomy & Space
Hi. If this is true for a black hole it would be true for any object.
2007-11-29 08:03:22 · answer #1 · answered by Cirric 7 · 1⤊ 0⤋
Currently the fastest-spinning black hole we have been able to measure rotates at 950 times per second.
When any mass, such as a star, becomes more compact than a certain limit, its own gravity becomes so strong that the object collapses to a singular point, a black hole. The spin of a star is thought to translate into spin of a black hole that forms from the star's collapse. With its mass much more compact, the spin rate ought to be phenomenal, much like a skater pulls in his arms to increase speed when performing a pirouette.
2007-11-29 08:48:25 · answer #2 · answered by Anonymous · 0⤊ 0⤋
As far as I understand, in addition to the schwartzchild-type surface defining the event horizon of a static black hole, the rotating version actually drags space-time round it. The surface of this region, the ergosphere, is bounded by another singularity associated with the changeover of space and time coords. In any case the constraints of v
2007-11-29 08:27:42 · answer #3 · answered by RTF 3 · 0⤊ 0⤋
A black hole is a point singularity, so has no limit to rotation. The event horizon has a radius > 0 but does not rotate as such as is not material
2007-11-29 07:16:52 · answer #4 · answered by Anonymous · 2⤊ 1⤋
The point of singularity that exists at the heart of a black hole is so incredibly small it has no spatial dimensions (although it is at the same time tremendouly heavy) - so the idea of trying to time it's rotations just doesn't make sense.
2007-11-29 13:56:21 · answer #5 · answered by Ms Minger 3 · 0⤊ 0⤋
A black hole is a dimensionless point in space. It's no bigger than the point of a pin.
The only indication of the amount of mass IN a black hole is how big the Event Horizon is. With each planet/star/person swallowed, the Event Horizon moves a little further out from the black hole itself.
2007-11-29 07:12:58 · answer #6 · answered by quantumclaustrophobe 7 · 2⤊ 2⤋
It has no surface. It is an infintesimally small point in space. The "even horizon" trails the rotation of the black hole and it's rotational period is therefore not problematic.
2007-11-29 07:29:57 · answer #7 · answered by Anonymous · 2⤊ 0⤋
A black hole has no size only mass, it's whats called a singularity the more mass it has the larger it's event horizon but the actual business bit is infinitesimal..
If you were to crush the earth down to a singularity its event horizon would be about the size of a marble
A spinning black hole does not spin as we would understand it but becomes a singularity ring
2007-11-29 07:17:58 · answer #8 · answered by Anonymous · 2⤊ 2⤋
A black hole does not have a diameter. It has an event horizon. Those are not the same. Try again. What you are looking for is a Kerr(-Newman) black hole:
http://en.wikipedia.org/wiki/Rotating_black_hole
http://en.wikipedia.org/wiki/Kerr_metric
2007-11-29 07:21:50 · answer #9 · answered by Anonymous · 3⤊ 0⤋
would the event horizon even bloody rotate?
its just a concept: "beyond this point, you are boned," not an actual ´thing´
right?!
so there´s no issue?!
2007-11-29 07:57:45 · answer #10 · answered by Anonymous · 1⤊ 1⤋