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a=?

2007-11-29 06:57:28 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

yeahh i mentt 7-a=6+5a

2007-11-29 07:15:23 · update #1

9 answers

You need an equal sign there. What does that equation equal? 0?

2007-11-29 07:00:51 · answer #1 · answered by thelegendmstr 4 · 1 0

Combine like terms:
7 - a + 6 + 5a =
(7 + 6) + (5a - a) =
13 + 4a =
4a + 13.
This isn't an equation, therefore, the value of 'a' can not be determined.

2007-11-29 15:04:40 · answer #2 · answered by Darlene 4 · 0 0

Simplifying
7 + -1a = 6 + 5a

Solving
7 + -1a = 6 + 5a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-5a' to each side of the equation.
7 + -1a + -5a = 6 + 5a + -5a

Combine like terms: -1a + -5a = -6a
7 + -6a = 6 + 5a + -5a

Combine like terms: 5a + -5a = 0
7 + -6a = 6 + 0
7 + -6a = 6

Add '-7' to each side of the equation.
7 + -7 + -6a = 6 + -7

Combine like terms: 7 + -7 = 0
0 + -6a = 6 + -7
-6a = 6 + -7

Combine like terms: 6 + -7 = -1
-6a = -1

a = 1/6

2007-11-29 15:27:13 · answer #3 · answered by Anonymous · 0 0

7 - a + 6 + 5a
Collect like terms ; that is numbers and values in 'a'.
13 + 4a
To find a value for 'a' the original statement has to be equated to some value, say '0' zero.
So:-
13 + 4a = 0 ( subtract 13 from both sides).
13 - 13 + 4a = 0 -13
4a = -13 ( divide both sides by 4).
4a/4 = -13/4
a = -13/4 (-3 1/4 = -3.25)

2007-11-29 15:08:48 · answer #4 · answered by lenpol7 7 · 0 0

Are you supposed to simplify?
4a+13
can't solve for a without = sign

Should it be
7-a=6+5a?
If so
-6a=-1
a=1/6

2007-11-29 15:03:31 · answer #5 · answered by RickSus R 5 · 0 0

7-a=6+5a
add a each sides
7=6+6a
subtract 6 each sides
a= 1/6

2007-11-29 15:59:14 · answer #6 · answered by $$$$$$$$$$$$$ 2 · 0 0

13/4 = a

2007-11-29 15:00:55 · answer #7 · answered by Tyler V 2 · 0 1

7-a=6+5a
-5a -5a
7-6a=6
-7 -7
-6a=-1
/-6 /-6
a= + 1/6

2007-11-29 15:29:14 · answer #8 · answered by Anonymous · 0 0

7-a=6+5a
7-6=a+5a
1=6a
a=(1/6)

2007-11-29 15:19:23 · answer #9 · answered by pstwoorbust 3 · 0 0

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