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1.Given the function f(x) = x2 - 6x + 8, find the y-coordinate of the vertex and list the ordered pair.
A.80 (-6, 80)
B.35 (-3, 35)
C.8 (6, 8)
D.-1 (3, -1)

2. Given the function f(x) = x2 - 6x + 8, find the x-coordinate of the vertex.
A.-6
B.-2
C.3
D.6

3.Given the function f(x) = x2 - 6x + 8, find f(-2). f(-2) =
A.-6
B.6
C.10
D.24

4.Solve the following quadratic equation.0 = x2 + 5x - 9
A.x = 2.5 and y = -15.25
B.x = 2.5 and y = 2.75
C.x = -1.405 and x = 6.405
D.x = 1.405 and x = -6.405

please help...will give 10 points to whom ever gets these right...please and thank you!

2007-11-29 06:02:52 · 3 answers · asked by MEB 2 in Science & Mathematics Mathematics

3 answers

1. f(x) = x^2 - 6x + 9 - 1 = (x-3)^2 - 1
Therefore, the answer is D.

2. f(x) = x^2 - 6x + 8 = (x-2)(x-4)
x-coordinate = (2+4)/2 = 3
Therefore, the answer is C.

3. D

4. x = (-5±√61)/2 = 1.405 and x = -6.405
Therefore, the answer is D.

2007-11-29 06:08:31 · answer #1 · answered by sahsjing 7 · 0 0

1.Given the function f(x) = x2 - 6x + 8, find the y-coordinate of the vertex and list the ordered pair.

C.8 (6, 8)

2. Given the function f(x) = x2 - 6x + 8, find the x-coordinate of the vertex.

C.3

3.Given the function f(x) = x2 - 6x + 8, find f(-2). f(-2) =

D.24

4.Solve the following quadratic equation.0 = x2 + 5x - 9

D.x = 1.405 and x = -6.405

2007-11-29 14:06:32 · answer #2 · answered by tinhnghichtlmt 3 · 0 0

f(x) = (x-3)^2 -1 so V(3,-1)
2) C
3)f(-2)=24
4) x= ((-5+-sqrt(25+36)9/2 solution D

2007-11-29 14:11:00 · answer #3 · answered by santmann2002 7 · 0 0

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