How would I write these two in general form...?

Question

1. Endpoints of a diameter are (5, 3) and (8, -3)

2. Endpoints of a diameter are (6, 9) and (4, 9)

Answer 1

Center is (6.5,0)
r^2 = 3^2+ 1.5^2 = 11.5
So x-6.5)^2 -y^2 = 11.5

Center is at (5,9)
r^2 = 1
So (x-5)^2+(y-9)^2 = 1

Answer 2

You can't solve a problem if you don't write it down correctly!
"General form" of what? The equation for circle?

The standard-form equation of a circle is
     (x - h)² + (y - k)² = r²
where the center of the circle is at (h,k) and the circle has radius r. You need to find values of h, k, and r².

The center of the circle is halfway between (6,9) and (4,9).
h = average of the x coordinates = (6+4)/2 = 5
k = average of the y coordinates + (9+9)/2 = 9
so the center is at (5,9).

The distance from the center (5,9) to (6,9) is equal to the radius. Think of the radius as the hypotenuse of a right triangle. By the Pythagorean Theorem,
r² = rise² + run²
= (9-9)² + (6-5)²
= 0² + 1²
= 1

The standard-form equation of this circle is
(x - 5)² + (y - 9)² = 1

Answer 3

if endpoints (5,3) and (8,-3), center is (13/2, 0) and diameter is
d² = (8-5)² + (-3 - 3)²
d² = 9 + 36 = 45
so r² = 45/4.
circle is
(x - 13/2)² + y² = 45/4

endpoints (6,9) and (4,9)
center is (5,9) radius (obviously) 1, so
(x-5)² + (y-9)² = 1