What are A, B and C in the polynomial 9x^2 + 4x + 69?

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Take A, B and C and find me the Sum, what is it? Now take that, divide it by 16 and subtract 4, what's the final answer?

2007-11-29 04:33:45 · 3 answers · asked by ton d 2 in Science & Mathematics ➔ Mathematics

A is 9, B is 4, and C is 69... sum of 82.... 5.125... final answer.... 1.125

2007-11-29 04:36:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋

A= 9, B= 4, C = 69

A+B+C = 82
(A+B+C)/16 - 4 = 82/16 - 4 = 1 1/8 = 1.125

2007-11-29 12:39:57 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋

Ax^2+Bx+C

so,
A=9
B=4
C=69

-4 + (A+B+C)/16

(9+4+69)/16 - 4 = 1.125

2007-11-29 12:37:00 · answer #3 · answered by KEYNARDO 5 · 0⤊ 0⤋