How do you balance these neutralization chemical equations?

Question

HCl + CaCO3 ---->
HCl + NaHCO3---->
HCl + KHCO3---->
I guess I am confused, because I believe water should be a product. Is there more than two products in some of these equations? I am so confused.

Answer 1

2 HCl + CaCO3 ----> CaCl2 + CO2 + H2O
HCl + NaHCO3----> NaCl + CO2 + H2O
HCl + KHCO3----> KCl + CO2 + H2O

Answer 2

These reaction don't produce water as a product because the bases don't have OH- attached to them. They go like this:

2HCl + CaCO3 ---> CaCl2 + H2CO3
HCl + NaHCO3 ---> NaCl + H2CO3
HCl + KHCO3 ---> KCl + H2CO3.

The way these reactions work, you have two ionic compounds, each of which has a cation and an anion. During the reaction, they switch partners, so the cation from the first compound goes with the anion from the second compound. The first reaction is in a 1:2 ratio because Ca and CO3 each have two charges (Ca 2+ and CO3 2-), so it takes two of the single-charged Cl- and H+ ions to balance them.

The reason you're expecting water is that strong bases have OH- as an anion. For instance, NaOH is a strong base. When it reacts with water, you get NaCl and HOH, more commonly written as H2O--water.

Answer 3

The important thing to recognize when neutralizing anything with a carbonate ion or the hydrogen carbonate ion (HCO3-) s that you'll initially form H2CO3 which decomposes into H2O and CO2. This is why baking soda (NaHCO3) fizzes when you pour any acid on it.

So, for the first one, the overall reaction will be:

2 HCl + CaCO3 --> CaCl2 + H2O + CO2

In the other two, you have HCO3- ions, and so you'll only need 1 HCl to react with each of those compounds.

Answer 4

Hcl Nahco3

Answer 5

2HCl + CaCO3 --> CaCl2 + H2O +CO2

HCl + NaHCO3 --> NaCl +H2O +CO2

HCl +KHCO3 ---> KCl + H20 + CO2

Answer 6

the product obtained is
2HCL + CaCO3=H2CO3 + CaCL2
HCL + NAHC03= H2CO3 + NACl
HCL + KHCO3= H2CO3 + KCl