w^2 - w^2 y^4 factor completely.?

Answer 1

[01]
w^2-w^2 y^4
=w^2(1-y^4)
=w^2{(1)^2-(y^2)^2}
\=w^2(1+y^2)(1-y^2)
=w^2(1+y^2){(1)^2-(y)^2}
=w^2(1+y^2)(1+y)(1-y)

Answer 2

w^2 - w^2 y^4

= w^2(1-y^4)
= w^2(1+y^2)(1-y^2)
= w^2(1+y^2)(1+y)(1-y)

Answer 3

Again, you should know how to do this by now with the help from the last two questions on factoring...