to keep the box moving across the floor at a constant velocity?
2007-11-29 01:41:46 · 2 answers · asked by lana l 1 in Science & Mathematics ➔ Physics
a. 23.9 N
b. 234.22 N
c. 901.6 N
d. 3468 N
2007-11-29 06:58:34 · update #1
The friction force is uN where u is the coefficient of friction and N is the normal force. In this problem, N is simply the weight of the box, mg, where g is 9.8 m/s^2. So the force required to keep the box moving at a constant velocity is
F = umg
2007-11-29 02:05:51 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋
The force of friction is equal to the coefficient times the normal force of the floor acting on the box. Because the floor is assumed to be level, the normal force will be mg = 92(9.81).
So the force of friction will be 0.26(92)(9.81). If the box is moving at a constant velocity, there is no acceleration and therefore the net forces acting on the box are equal to zero. So the force needed to keep the box moving at a constant velocity is equal to the force of friction which is
0.26(92)(9.81) Newtons.
2007-11-29 10:10:59 · answer #2 · answered by cmbtkllr 2 · 0⤊ 0⤋