intro to electrical engineering class work help?

Question

A current of 5 [A] is flowing from left to right through a wire. The actual charges that are
moving inside the wire are electrons. Calculate how many electrons move past a given point
on the wire (moving from right to left), in a time of 60 [s].

How do i solve this problem?

Answer 1

q = I t ...q is charge, I is electric current, t is time
q = 5 x 60 = 300 coulombs

Now charge of 1 electron = 1.6 x 10^(-19) Coulombs
so 300 coulombs means (300 / 1.6) x 10^19 Coulombs
= 187.5 x 10^19 electrons

Answer 2

1 coulomb is the amount of electrical charge in 6.241506×10^18 electrons or other elementary charged particles.
The charge of one electron is equal to
-1.602176×10^-19 C
Other than that; the previous guy almost got it right.
5*60*6.241506×10^18 =
1872451800000000000000=
1.8724518E21 electrons
Note: Electrons have a negative charge and assuming you meant "conventional current" (The arbitrary standard that electricity flows from positive to negative) the number should have a negative sign on it.
so:
-1.8724518E21 electrons
I usually lose the best answer for being such a stickler but it you look at any circuit diagram of a diode or a transistor you will notice that the arrows always point from the positive to the negative. This is conventional current flow from before they realized that electrons had a negative charge.

Answer 3

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Answer 4

1 Amp = 1 Coulomb/sec

1 Coulomb = 1.6021892^(19) electrons

Electrons passing at one given point with a current of 5 Amp for a period of 60 seconds =

=5x60x1.6021892^(19)

Answer 5

I'ld start with finding out how many electrons are in an ampere of current per given time unit. I bet it's in seconds!

Answer 6

Current -i
Charge- q
time - t

current is the rate of flow of charge . So at a point
i=q/t .
=>q= i*t
=>your answer