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1. aabb
2. Aabb
3.AaBb
4.AABb

Please anyone could help me this about genetics. Thank you

2007-11-27 07:55:30 · 2 answers · asked by mama bear 1 in Science & Mathematics Botany

2 answers

I could reel off the percentages, but come test time you would be stuck. This analysis calls for a punnett square. Go to the web site below, read and work the examples. You will be surprised how easy it is.

2007-11-27 09:32:23 · answer #1 · answered by Anonymous · 0 0

To figure probability one looks over the number of chances first.
The gamete only gets one out of a choice of two parental alleles. These genes are independent so can be considered separately.
Parental gene has two alleles A or a => Gamete
The question wants only a so it would be 1/2 (one is 'a' out of two alleles)
B or b => gamete is the same 1/2

#1 aabb
a or a => only allele of choice so 2/2
b or b => only allele of choice so again 2/2
1x1 = 1 or all the gametes

#2 Aabb
1/2 x 2/2 = 1/2 the gametes

#3 AaBb
1/2x1/2 = 1/4

# 4 AABb
0/2x1/2

2007-11-27 18:16:01 · answer #2 · answered by gardengallivant 7 · 0 0

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