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What is the difference between butterworth n=3, n=5 and n=7

2007-11-24 20:41:27 · 3 answers · asked by David Junior 3 in Science & Mathematics Engineering

3 answers

A butterworth filter is a analog filter design, it has a formula for calculating the poles of the transfer function for a low pass. the n=3, n=5. . . is the filter order. the filter order for a butterworth is simply the order of the polynomial thats in the denominator in the transfer funtion, you can read more information here: http://en.wikipedia.org/wiki/Butterworth_filter
they even show you the formula for calculating the coeffecients

2007-11-24 21:33:55 · answer #1 · answered by pfultz2 2 · 0 0

it is definitely truly a tough mission, going from a move function to an LC ladder filter out. it truly is surely no longer trivial for an eighth-order filter out. If I had to do it (yet i could avert LC filters like the plague at low frequencies!), my first port of call can be a common reference textual content which tabulates values for LC ladder filters. because the Butterworth is a very established filter out function, it truly is sure to be in there. The e book will regularly grant you with a filter out layout with a cutoff angular frequency of omega = a million rad/s and source and shipment impedances of one million ohm. then you favor to scale it for frequency, and then rescale it for impedance. A extra effective 2Hz filter out could use op amps. you are able to do it with 4 2d-order sections, yet there are probable fancier techniques requiring fewer op amps. besides, you'll favor 8 capacitors and a group of resistors. lately filter out layout is achieved utilising pcs, numerical simulation and optimisation routines, which takes each of the hardship out of it. it is also basic to check out the outcome of element tolerances.

2016-10-25 01:05:49 · answer #2 · answered by ? 4 · 0 0

If you click on Google and do a search, you should find your answer there. There is a mass of information and you should be able to sort everything out.


www.save-money-guide.com

2007-11-24 20:46:20 · answer #3 · answered by Anonymous · 0 0

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