By the rule of the dice (craps) game every numbers can be bought.
however, when I ask to buy 5 and 9 -despite it has the same vigorish as 4 and 10 (because they dont count cents) and still I win tough a fools bet it is.
What do you think?
2007-11-23 21:04:15 · 2 answers · asked by Anonymous in Games & Recreation ➔ Gambling
Despite all of your math, the stickman placing the dice to the suckers that 4 and 9 comes out favorably before a seven out - many times.
2007-11-25 02:30:30 · update #1
No, I have never bought the 5 or 9 in craps. Few people buy any numbers other than 4 or 10. The reason is the vigorish is the same for any number, giving the house a 4.76% edge. If you use place the numbers instead of buying them the house edge varies by number and is
6.67% for 4 or 10
4.00% for 5 or 9
1.52% for 6 or 8.
Hence, buying the 4 and 10 has a lower house edge than placing them, while placing the 5, 6, 8, and 10 has a lower house edge than buying them.
There is one variation on the buy bet used by a few casinos than would make buying the 5 and 9 a better bet than placing them. This variation requires you to only pay the commission on a buy bet when you win. With that rule variation the house edge for buy bets is
1.67% for 4 or 10
2.00% for 5 or 9
2.27% for 6 or 8
Hence, with that rule variation buying the 4, 5, 9 and 10 has a lower house edge than placing them, while placing the 6 and 8 has a lower house edge than buying them.
2007-11-24 01:41:41 · answer #1 · answered by zman492 7 · 1⤊ 0⤋
no
2007-11-23 21:07:59 · answer #2 · answered by Anonymous · 0⤊ 0⤋