I have 12 games in football
there are 24 teams playing
12 of them are favorites and 12 of them are underdogs
what is the number of probabilities or combinations of the underdogs/favorites wining ?
study this:
U - underdog
F-favorite
prob - probability
TEAM prob1 prob2 prob3 >>>>>>>>>>>until prob. X
1 F U U
2 F F U
3 F F F
4 F F F
5 F F F
6 F F F
7 F F F
8 F F F
9 F F F
10 F F F
11 F F F
12 F F F
Now I want to know how many probabilities can happen...
Thanks
2007-11-23 15:26:44 · 5 answers · asked by ZIlph 2 in Games & Recreation ➔ Gambling
50 combinations with you can choose from
2007-11-23 20:26:59 · answer #1 · answered by thezinger79 2 · 0⤊ 1⤋
What you want to know is the number of occurrences.512. the payoff is about 1 to 3 for a total rap parlay. Which mean if you bet all you lose.By the way 2^12 is 512.
2007-11-24 01:54:36 · answer #2 · answered by Wylie Coyote 6 · 0⤊ 0⤋
You have 12 independent events that can each occur in one of two possible outcomes.
The total number of outcomes is 2^12, or 4096.
For computer people: This is exactly the same as a twelve-bit binary number, where each bit can be zero or one.
2007-11-24 12:17:59 · answer #3 · answered by John F 6 · 0⤊ 1⤋
I am pretty good at math but I don't really understand your question or the table you drew. I though only 2 teams played in a game of football but you have three entries.
2007-11-23 23:37:10 · answer #4 · answered by Mark H 2 · 0⤊ 1⤋
41472...
2007-11-23 23:34:02 · answer #5 · answered by Hello? 1 · 0⤊ 1⤋