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What is the rate flow through this section of the pipe?

2007-11-23 08:08:43 · 3 answers · asked by Gio 3 in Science & Mathematics Engineering

3 answers

3cm^2 x 18cm/sec = 54 cm^3/sec

2007-11-23 11:50:17 · answer #1 · answered by Tim C 7 · 0 1

The speed of the flow differ between the center and the sides. The speed of 18 cm\s is therefore an average speed.
An area is given in square units and assumed to be 3 cm ^2
The volume is therefore 3cm^2 x 18cm = 54 cm^3.

2007-11-23 08:29:13 · answer #2 · answered by watergump44 4 · 0 1

If you have the average speed and cross sectional area of the pipe calculating the flow is actually pretty easy. You just multiply the two:

Q = V A

I'm just worried about the unit of area of the pipe, it should actually be 3.00 cm^2 for area.

2007-11-23 21:35:08 · answer #3 · answered by Anonymous · 1 0

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