Seems to me, she is the one who is homophobic...doesn't it?
2007-11-19 09:07:17 · 15 answers · asked by Star 5 in Society & Culture ➔ Religion & Spirituality
I think Francine is none other than Ted Haggard and Francine's boyfriend is actually Larry Craig.
2007-11-19 09:11:06 · answer #1 · answered by Pangloss (Ancora Imparo) AFA 7 · 3⤊ 0⤋
Nothing about Francine is real. She may be a "he."
The only thing I am sure of is that Francine is not a Christian or an atheist. She or he is NOTHING.
My lemur friend, you are so wrong.
I don't know of ANY Christians who think that way.
2007-11-19 17:39:04 · answer #2 · answered by batgirl2good 7 · 1⤊ 0⤋
Francine is his own boyfriend.
Frank is someone with problems. For all I know, he may be an atheist having fun.
2007-11-19 19:14:47 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Francine is Francine's boyfriend.
2007-11-19 17:10:19 · answer #4 · answered by What? Me Worry? 7 · 2⤊ 0⤋
who the poot is Francine?
if she reads like a homophobe and sounds like a homophobe...then shes either a homophobe...or a closeted homosexual herself.
50-50 chance...
2007-11-19 17:09:31 · answer #5 · answered by johnny.zondo 6 · 1⤊ 0⤋
She's a troll. Whether she has a boyfriend or not is inconsequential. Plenty of guys are homophobic, so I'm not going to say it's impossible.
2007-11-19 17:09:59 · answer #6 · answered by Anonymous · 1⤊ 0⤋
You have to be a human being to have a boyfriend.
I don't think she qualifies. Boxer and Pit Bull, or Doberman comes to mind
2007-11-19 17:41:49 · answer #7 · answered by moonbaby 2 · 0⤊ 0⤋
It's 97th account has probably all ready been deleted. Personally I find it humorous and I really believe that deep down inside that is how a lot of Christians think.
2007-11-19 17:12:34 · answer #8 · answered by Anonymous · 3⤊ 1⤋
Go to the Immature and Silly forum, OK?
2007-11-19 17:10:11 · answer #9 · answered by rico3151 6 · 1⤊ 0⤋
I've always been under the impression that "she" is a he who does in fact have a boyfriend.
2007-11-19 17:10:56 · answer #10 · answered by Celestian Vega 6 · 4⤊ 0⤋