Determine the number of moles of Krypton contained in a 3.25 liter gas tank at 5.80 atm and 25.5 °C.
If the gas is Oxygen instead of Krypton; will the answer be the same? Why or why not?
I'm pretty sure the equation n=PV/RT should be used in this problem. All the information is given for it except for R, which is a constant, that can change.... confusing.
2007-11-14 17:28:51 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The way you do this is set up the equation to solve for moles as given below, then plug in the numbers. Make certian the values given are in the proper units! In this case they are all OK except for temperature; 25.5 C = 25.5 + 273.15 = 298.6K
PV=nRT solving for n: n = PV/RT
Now, plug in the values:
n = (5.80atm x 3.25L)/(0.08206Latm/molK x 298.6K) =
0.769moles
If the gas was oxygen, the number of moles would be the same. It has been determined that a mole of any gas at STP is about 22.4 liters. This is because a gas is mostly empty space between atoms/molecules flying around so the size of the atoms/molecules has very little effect on volume or pressure, only the weight & density of the gas.
2007-11-14 17:48:54 · answer #1 · answered by Flying Dragon 7 · 0⤊ 0⤋
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2016-05-17 09:11:59 · answer #2 · answered by ? 4 · 0⤊ 0⤋
R will always be .0821 "L atm/mol K" when you use the ideal gas law pv = nrt, provided that P is in atm, V is in Liters, and T is in kelvin
the answer will be the same if its Kr instead of O, because at STP, one mole of any gas is always 22.4L
avogadro's gas law state that the volume of a gas is always be directly proportional to the moles of the gas, regardless of the gas's size or mass (in other words, it doesn't matter what gas it is)
you need to remember to convert the temperature from C to K before you can use the gas constant
the number of moles in this problem will be (5.8)(3.25)/(25.5+273)(.0821)
2007-11-14 17:34:41 · answer #3 · answered by icie 3 · 1⤊ 0⤋
The mols of Oxygen and Krypton will be the same.
You are correct that n = PV/RT will work for you.
You should choose the R you want, in this situation you should use 0.0821 atm * L / mol * K.
2007-11-14 17:35:29 · answer #4 · answered by Seraph 2 · 0⤊ 0⤋
Ask the teacher how to do it
2016-03-14 13:58:44 · answer #5 · answered by Anonymous · 0⤊ 0⤋
huh?
2007-11-14 17:30:54 · answer #6 · answered by Chris J 2 · 0⤊ 0⤋