how exactly do i find the difference between two different radius' r= C/2(3.14) and r=(C+1)/2(3.14)?

Question

I need the steps and the answer

Answer 1

let's call the 2 radii a and b, so
a = c/(2π) and b = (c+1)/(2π), and
a-b = c/(2π) - (c+1)/(2π)
a-b = [c - (c+1)]/(2π)
a-b = -1 / (2π)

and of course b-a = 1 / (2π)
in case you wanted the difference the other way.

Answer 2

r = C/2(3.14)
Let the r in 2nd equation be called R, then 2nd equation becomes
R=(C+1)/2(3.14)
So the difference between the to radii is
R-r=[(C+1)/2(3.14)]-[C/2(3.14)]
or R-r=1/2(3.14)[(C+1)-C)]
or R-r=1/2(3.14)(1) ..... (The 2 C's cancel out)
or R-r=1/2(3.14)
or R-r=1/6.18
R-r=0.159 .... that is the answer.

PS:- I feel the question should be how exactly do i find the difference between two different radius' r= [C/2](3.14) and r=[(C+1)/2](3.14)?
Then the difference between the two radii will be 1.57

Answer 3

(C+1)/6.28 = C/6.28 + 1/6.28
(C=1)/6.28 - C/6.28 = C/6.28 + 1/6.28 -C/6.28 = 1/6.28 = .16foot = 1.91 inches