vertex form of 6x²+7x-5?

Question

information on how to find the vertex form would be more helpful then the actual answer

more so what is it in form y=a(x-h)²+k
h,k being the vertex

Answer 1

y = 6x² + 7x - 5
y = 6(x² + (7/6) x - 5/6)
y = 6 (x² + (7/6) x + 49/144 - 49/144 - 5/6)
y = 6(x² + (7/6) x + 49/144) - 49/24 - 5
y = 6(x + 7/12)² - 169/24
Vertex (-7/12, -169/24)

Answer 2

y = 6x²+7x-5
(1/6)y = x²+(7/6)x-5/6 //Dividing both sides by 6
(1/6)y = x²+(7/6)x+(49/144)-169/144 //Completing the square
(1/6)(y + 169/24) = (x + 7/12)² //Rearranging and factoring

There you have it!

Vertex form means it basically has the vertex at (-7/12, -169/24), since that's where the equation ended up. Also, the 1/6 coefficient on y shows how steep the parabola is.

Answer 3

I calculate on my calculator and got x= -(negative).5833 and y= -(negative)7.0417. Does that help?