Can someone show me how to solve this? I am just trying to check an answer to see if I have the right answer or where I might of made mistakes.
http://img.photobucket.com/albums/v60/simple_3/math2-1.jpg
2007-11-14 15:41:11 · 2 answers · asked by . 2 in Science & Mathematics ➔ Mathematics
3x² > 2(x + 4)
3x² > 2x + 8
3x² - 2x - 8 > 0
(3x + 4)(x - 2) > 0
3x + 4 > 0 and x-2 > 0 gives x > - 4/3 , x > 2
3x + 4 < 0 and x - 2 < 0 gives x < - 4/3 , x < 2
Solution is x < - 4/3 , x > 2
2007-11-14 20:46:49 · answer #1 · answered by Como 7 · 2⤊ 1⤋
Answers x < -4, -4/3< x< 0, 2< x . You cannot "cross multiply" in working this problem. Rather subtract the 2/x from both sides , common denominator, subtract, factor top and bottom, place the zeros of these factors on a number line, check the validity of the inequality at any point in between these zeros.
2007-11-15 00:16:06 · answer #2 · answered by ted s 7 · 0⤊ 1⤋