2007-11-14 15:35:40 · 6 answers · asked by bob joe bill 2 in Science & Mathematics ➔ Mathematics
1
2007-11-14 15:42:44 · answer #1 · answered by ba$$hunter 2 · 0⤊ 0⤋
1
2007-11-14 15:39:57 · answer #2 · answered by Anonymous · 0⤊ 0⤋
There is only 1
The factors of 27 is 3^3 = 9 x 3
16 is 2^3 = 8 x2
and 78 is an even # so it is a base 2
2007-11-14 15:40:16 · answer #3 · answered by Ronatnyu 7 · 0⤊ 0⤋
i think the gcf is 1
the highest it could possibly be (theoretically) is 16 since thats the lowest number in the set
16 doesn't go in to 27
neither does 15
or 14
or 13
or 12
or 11
or 10
9 goes into 27 but not into 16
or 8
or 7
or 6
or 5
or 4
3 goes into 27 but not 16
or 2
and 1 goes into every number
so the answer is one
2007-11-14 15:41:47 · answer #4 · answered by Chris 2 · 0⤊ 0⤋
1 (since 16 = 2^4 and 27 = 3^3 have no common factors).
.
2007-11-14 15:37:40 · answer #5 · answered by tsr21 6 · 0⤊ 0⤋
There ain't one. 27 is 3 times 3 times 3. 16 is 2 times 2 times 2 times 2 times... Oh, rats.
2007-11-14 15:38:09 · answer #6 · answered by Firebird 7 · 0⤊ 0⤋