Calculate w and E when one mole of a liquid is vaporized at its boiling point (89°C) and 1.00 atm pressure.?

0 ⤊

Calculate w and E when one mole of a liquid is vaporized at its boiling point (89°C) and 1.00 atm pressure.?

Hvap for the liquid is 40.2 kJ mol-1 at 89°C.

2007-11-14 14:50:18 · 1 answers · asked by Sean D 2 in Science & Mathematics ➔ Chemistry

1 answers

Please follow the general procedure I used to solve an almost identical problem:
http://answers.yahoo.com/question/index;_ylt=Agm.LoWQ6WNAHlYvGhjhMzbsy6IX;_ylv=3?qid=20071114182840AATuhjI&show=7#profile-info-rpTSnSzQaa

2007-11-15 19:00:26 · answer #1 · answered by Hahaha 7 · 0⤊ 0⤋