Solve: 0.4(x-3)=0.04(3x + 40)
2007-11-14 14:39:16 · 7 answers · asked by ? 2 in Science & Mathematics ➔ Mathematics
0.4x - 1.2 = 0.12 + 1.6
0.4x - 0.12x = 1.6 + 1.2
0.28x = 2.8
divide both side by 0.28 to get the x
x = 10
2007-11-14 15:15:37 · answer #1 · answered by Periwinkle 2 · 0⤊ 0⤋
Multiply both sides by 25
10(x-3) = (3x + 40)
distribute the '10' on the left:
10x - 30 = 3x + 40
subtract 3x from both sides
7 x -30 = 40
add 30 to both sides
7x = 70
2007-11-14 22:43:31 · answer #2 · answered by Raymond 7 · 0⤊ 1⤋
0.4(x-3)=0.04(3x+40)............given.sum
or 0.4(x-3)x100 = 0.04(3x+40)x100........to rid of decimal
0r 40x - 120 = 12x + 160
or 40x - 12x = 160+120
0r 28x = 280
or x = 10 (solved)
2007-11-14 23:07:34 · answer #3 · answered by nazbak 6 · 0⤊ 0⤋
10(x-3) =3x+40
10x-30 =3x+40
7x=70
x=10
2007-11-14 22:44:06 · answer #4 · answered by Anonymous · 0⤊ 1⤋
0.4(x-3)=0.04(3x+40)
0.4x-1.2=0.12+1.6
0.4x = 1.72+1.2
0.4x =2.92
x=7.3
2007-11-14 22:46:27 · answer #5 · answered by Kenneth Koh 5 · 0⤊ 1⤋
multiply each side by 100 first to make things simple
40x-120=12x+160
28x=280
x=10
2007-11-14 22:43:27 · answer #6 · answered by mathwhiz620 2 · 0⤊ 1⤋
.4x - 1.2 = .12x + 1.6
-2.8 = -0.28x
10 = x
2007-11-14 22:42:53 · answer #7 · answered by Ms. Exxclusive 5 · 0⤊ 1⤋