What is the perimeter of a square with a diagonal of 3√2?.?

Question

i do not know what the hell this means

Answer 1

We must find a side of the square.
We have s² + s² = 9*2
So 2s² = 18
s² = 9
s = 3
Perimeter= 4s = 12
Sorry, I misread 3√2 as 3/√2 before

Answer 2

Draw a square and draw in the diagonal. The diagonal's length is 3(sqrt 2). The diagonal and two sides of the square form a right triangle, with the diagonal as the hypotenuse.

The Pythagorean theorem says the square of the hypotenuse is equal to the sum of the squares of the other two sides. Since this is a square, those two sides are equal.

So let's call the length of those sides x. Square each of them and add them together, and you have 2x^2. That equals the square of the diagonal, or 9 times 2 (Square the 3 and square the sqrt 2 and multiply them together.)

So 2x^2 = 18, and x^2 = 9. Now you can find x; multiply the value of x by 4 to get the perimeter (all four sides are equal in a square).

Answer 3

the diagonal breaks the square up into 2 right triangles. so use the pythagoriam theorem a^2+b^2=c^2
beacause a and b are the same size it become 2a^2=c^2
2a^2=(3sqrt2)^2
2a^2=18
a^2=9
a=3
3+3+3+3=12

Answer 4

The perimeter is 12 because each side will be 3.

Answer 5

i dont have a calculator but you would do this: sin(45) = x/(3(root 2)) isolate x. then multiply it by four