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A bicycle has wheels 0.94 m in diameter. The bicyclist accelerates from rest with constant accleration to 7.52 m/s in 5.57 seconds.

What is the angular acceleration of the wheels?


Then you are given

α= 1.47 rad/s/s and t=2.41 s.

How many revolutions does it go through?

2007-11-14 14:22:33 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

First, convert the translational speed to angular speed of the wheels

v/r=w
7.52*2/0.94
w=16 rad/sec
From rest with constant α
w=α*t
16=α*5.57
α=2.87 rad/s^2


The second part, from rest, the angle of displacement, th is
th=.5*α*t^2
th=.5*1.47*5.57^2
th=22.8 radians
one rev = 2*pi radians
22.8/(2*3.14)
3.63 revs

j

2007-11-15 12:06:57 · answer #1 · answered by odu83 7 · 0 0

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