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1. 9x + 7 / 2 + 9x - 2 / 5 = -2/3
I came up with 73/179x.

2. (-4 - 9i)(-4 - 9i)
I came up with 16 - 81i^2

3. (r + 6)^2 = 13
I came up with r = -6 + sqrt 13 or r = -6 - sqrt 13

4. Absolute value of 3x - 4 >/equal to 8
I came up with x >/equal to 4/3

5. 10y = 7y + 6 + 2y
I came up with y = 6

How'd I do? If I screwed up, help would be appreciated!!!

2007-11-14 14:03:11 · 4 answers · asked by wrongnumber 1 in Science & Mathematics Mathematics

4 answers

1. 18x=-2/3+2/5-7/2
x=-113/540

2. (-4 - 9i)(-4 - 9i)=16+72i+81i^2=16+72i+81(-1)^2
=16+72i+81=97+72i

3. correct

4. 3x-4>=8
3x>=12
x>=4

5. correct

2007-11-14 14:16:00 · answer #1 · answered by Kenneth 4 · 0 0

1. you need to solve for x.
2. You left out 72i, your answer should be 16+72i+81i^2
3.r^2 + 12r + 36=13 (solve from there)
4.x≥4 and x≤-4/3
5. correct

2007-11-14 22:21:18 · answer #2 · answered by Andy L 1 · 0 0

#1 is not right. are you solving for x? if so, x=-113/540

#2 wrong 16-81i^2+72i

#3 right

#4 wrong x>=4 or x<=-4/3

#5 correct

2007-11-14 22:15:35 · answer #3 · answered by info2know 3 · 0 0

1.srry dunno
2.srry dunno
3.TRUE
4.TRue
5.True

2007-11-14 22:15:34 · answer #4 · answered by yaso 2 · 0 2

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