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the circumference of a circle and the perimeter of a square can intersect at a maximum of ? points

2007-11-14 14:00:25 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

I think it is 8 points. Think of a circle centered on the square but with a diameter bigger than a side of the square. The circumference will cut each side at 2 points so that makes 8 for 4 sides of square.

2007-11-14 14:05:41 · answer #1 · answered by Rich Z 7 · 0 0

8.

The smallest circle that would intersect a square would be inscribed inside the square - meaning that each line of the square would be tangent to the circle's circumference. This would give you 4 intersection points.

The largest circle would be circumscribed meaning that all four corners of the square lie on the perimeter of the circle. This would give 4 intersection points.

So any circle greater than the inscribed and smaller than the circumscribed would have two intersection points on each leg of the square. 4 legs equals eight intersections.

2007-11-14 14:13:50 · answer #2 · answered by J T T 1 · 0 0

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