Standard cell potentials are determined with 1.0 M solutions of ions. In this experiment, we will use 0.10 M solutions of Zn2+, Cu2+, Pb2+, and Ag1+ to minimize the amount of hazardous waste generated. In this series of questions, you will figure out what effect this will have on the voltages you observe.
Consider a cell consisting of a Cu2+/Cu couple, and a Ni2+/Ni couple.
a. Starting with 1.0 M solutions of ions (standard conditions), evaluate Q in the Nerst Equation.
2007-11-14 13:50:20 · 1 answers · asked by flaquita 1 in Science & Mathematics ➔ Chemistry
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Further, when both [Cu(2+)] and [Ni(2+)] drop to 0.1M,
Q = [Ni(2+)] / [Cu(2+)] is still 1. That is why said "In this experiment, we will use 0.10 M solutions of Zn2+, Cu2+, Pb2+, and Ag1+ to minimize the amount of hazardous waste generated....."
2007-11-16 16:10:45 · answer #1 · answered by Hahaha 7 · 0⤊ 0⤋