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Okay so a normal male and a female carrier for color blindness produce 6 female children and 5 males. None of the males are colorblind. Sooo... how do you find out how many females are color blind? and would this be an example of X-linked recessive?

2007-11-14 13:43:46 · 2 answers · asked by Anonymous in Science & Mathematics Biology

2 answers

Colorblindness is an X-linked recessive disorder.
We're doing this in AP Bio right now.

So you would make a punnett square with the normal male (xAy) and the female carrier (xAxa) to get the offspring :
xAxA xAy
xAxa xay

1/2 of the females would be carriers, 1/2 of the females would be homozygous noncolorblind, 1/2 of the males would be colorblind, and half of the males wouldn't be colorblind. (Theoretically)

So none of the females are colorblind.

2007-11-14 13:50:38 · answer #1 · answered by violingirl7777 3 · 1 0

None of the daughters is color blind. The color blindness is X chromosome linked. Since the father is normal, the daughters are either a carrier or a non-carrier (normal).

2007-11-14 13:58:37 · answer #2 · answered by OKIM IM 7 · 0 0

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