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A physics professor is pushed up a ramp inclined upward at an angle theta above the horizontal as he sits in his desk chair that slides on frictionless rollers. The combined mass of the professor and chair is m. He is pushed a distance x along the incline by a group of students who together exert a constant horizontal force of F. The professor's speed at the bottom of the ramp is v.

Problem:
Use the work-energy theorem to find his speed at the top of the ramp.

I've tried this problem over 7 times, please help

2007-11-14 13:40:09 · 1 answers · asked by Anonymous in Science & Mathematics Physics

sojsail thats wrong, apparently mass isn;t even a variable in the solution

2007-11-14 15:46:24 · update #1

1 answers

Work done, W = F*x.
Kinetic energy at the bottom, KEb = (1/2)*m*v^2

Potential energy gained, PE = m*g*h
where h is the height at the top, h = x*sin(theta)
Kinetic energy at the top, KEt = (1/2)*m*vt^2

W + KEb = PE + KEt

2007-11-14 14:57:46 · answer #1 · answered by sojsail 7 · 0 0

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