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7 answers

=(2x + 1 + x)/(5x -2 -x)
=(3x + 1)/(4x-2)

2007-11-14 13:35:24 · answer #1 · answered by Edward 7 · 0 0

first, you combine like terms in the numerator ( 2+1= 3) then in the denominator (5-1=4)
so you would have (3+1/x) / (4 -2/x)

since the numerator and the denominator have both a denominator x. then we can multiply top and bottom by x in order to get rid of that x.

so then we would have the following:
(1+3x)/(-2 +4x)

remember;
when multiplying top and bottom by x.
the x in (1/x) and (-2/x) disappear, but you would still have to multiply the other term by x (3) in the numerator and (4) in the denominator.

hope this helps.! =)

2007-11-14 21:47:32 · answer #2 · answered by tita 2 · 0 0

Well first start by adding like terms
(3/x+1)/(3/x-1)
Now since you are dividing it is the same thing as multiplying by the reciprocal.
So now you get
(3/x+1) * (x-1/3)
Multiplying this out you get
(3x-3)/(3x+3)
Same as
3(x-1) / 3(x+1)
This simplified is
(x-1) / (x+1) and that is your final answer

2007-11-14 21:37:38 · answer #3 · answered by Jamanski 3 · 0 0

(2+1/x+1) + (5- 2/x -1)

= (10 - 4/x -2) + (5/x -2/2x-1/x) + (5- 2/x -1)
=10 -4/x -2 + 5/x -2/2x -1/x + (5-2/x-1)
=10 -2/2x -2 +5 -2/x -1
= 12- 2/2x -2/x

2007-11-14 21:40:09 · answer #4 · answered by Misspompom 4 · 0 0

(3/x+1)/(3/x-1)

=]

2007-11-14 21:34:50 · answer #5 · answered by Anonymous · 0 0

I'm not sure what you're trying to do, but try finding the common denominator of the top and bottom:
[(2x+1+x)/x]/[(5x-2-x)/x]
=(3x+1)/(4x-2)

2007-11-14 21:37:26 · answer #6 · answered by Chaosgnaw 1 · 0 0

Tita is correct

2007-11-14 22:21:09 · answer #7 · answered by mrmuttisme 1 · 0 0

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