=(2x + 1 + x)/(5x -2 -x)
=(3x + 1)/(4x-2)
2007-11-14 13:35:24
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answer #1
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answered by Edward 7
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first, you combine like terms in the numerator ( 2+1= 3) then in the denominator (5-1=4)
so you would have (3+1/x) / (4 -2/x)
since the numerator and the denominator have both a denominator x. then we can multiply top and bottom by x in order to get rid of that x.
so then we would have the following:
(1+3x)/(-2 +4x)
remember;
when multiplying top and bottom by x.
the x in (1/x) and (-2/x) disappear, but you would still have to multiply the other term by x (3) in the numerator and (4) in the denominator.
hope this helps.! =)
2007-11-14 21:47:32
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answer #2
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answered by tita 2
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Well first start by adding like terms
(3/x+1)/(3/x-1)
Now since you are dividing it is the same thing as multiplying by the reciprocal.
So now you get
(3/x+1) * (x-1/3)
Multiplying this out you get
(3x-3)/(3x+3)
Same as
3(x-1) / 3(x+1)
This simplified is
(x-1) / (x+1) and that is your final answer
2007-11-14 21:37:38
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answer #3
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answered by Jamanski 3
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(2+1/x+1) + (5- 2/x -1)
= (10 - 4/x -2) + (5/x -2/2x-1/x) + (5- 2/x -1)
=10 -4/x -2 + 5/x -2/2x -1/x + (5-2/x-1)
=10 -2/2x -2 +5 -2/x -1
= 12- 2/2x -2/x
2007-11-14 21:40:09
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answer #4
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answered by Misspompom 4
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(3/x+1)/(3/x-1)
=]
2007-11-14 21:34:50
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answer #5
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answered by Anonymous
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I'm not sure what you're trying to do, but try finding the common denominator of the top and bottom:
[(2x+1+x)/x]/[(5x-2-x)/x]
=(3x+1)/(4x-2)
2007-11-14 21:37:26
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answer #6
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answered by Chaosgnaw 1
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Tita is correct
2007-11-14 22:21:09
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answer #7
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answered by mrmuttisme 1
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