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1 -2 3 2
2 -1 0 4
-3 4 0 -2
-1 1 1 5

2007-11-14 13:13:03 · 4 answers · asked by Sidney 1 in Science & Mathematics Mathematics

4 answers

Go across the first row, take each number times the determinant of the 3x3 matrix formed by eliminating the row and column that number is in. As you go across, alternately add and subtract the product.

So, det(your 4x4) = 1 * det(3x3) - (-2) * det(3x3) + 3 * det(3x3) - 2 * det(3x3)

where each "3x3" is found as described above. You can do the same recursively to find each 3x3 determinant.

2007-11-14 13:33:49 · answer #1 · answered by Andy J 7 · 0 0

Solve 4x4 Determinant

2016-12-11 19:11:40 · answer #2 · answered by corral 4 · 0 0

its a ***** to do but its possible

cross out the first column and the first row. then youre left with a 1 and a 3x3 matrix

-1 0 4
4 0 -2
1 1 5

and then find the determinant of that matrix and mulitply by 1 and so on

if you have a graphing calculator hit 2nd and the matrx. then gon to edit and press enter. type in the numbers of your matrix. press 2nd matrix again and then go to math and hit det(. press 2nd matrix again and go to [A] and press enter. then hit enter and it will give you the answer

2007-11-14 13:30:15 · answer #3 · answered by gabriel_d_popuch 1 · 0 0

Rubix cubes I just take off the stickers N put'em Back

2016-03-13 23:10:13 · answer #4 · answered by Anonymous · 0 0

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