Adam rolled two standard, six sided dice once. what is the probability that he did not roll a prime number on either die? [common fraction]..remember that 36 things can happen!
2007-11-14 13:04:27 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The prime numbers on each die are 2,3, and 5
That means you have 1/2 chance of not getting a prime number with each roll.
Since you have two dice, multiply 1/2 x 1/2 and you get a 1/4 chance of not rolling a prime number on either die.
2007-11-14 13:08:03 · answer #1 · answered by Anonymous · 1⤊ 1⤋
If you don't have a prime number on either die,
there can't be a 2,3 or 5 on either cube.
So the first cube can only be a 1,4 or 6.
Pairing these with the possibilities from the second cube
yields the following sample space:
1 1, 1 4, 1 6, 4 1, 4 4, 4 6, 6 1, 6 4 and 6 6.
9 possibilities in all.
So the required probability is 9/36 or 1/4.
2007-11-14 21:15:56 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
He has a chance of rolling a 2,4 or 6 out of 6 chances (on the first die) are 3 out of 6 or 1/2. He has the same chance for the next one. He has 50/50 odds of not rolling a prime.
2007-11-14 21:08:06 · answer #3 · answered by Lynn A 4 · 0⤊ 2⤋
well theres a 2/6 chance he'll roll a non prime number on one die and a 2/12 chance he'll get 2 non prime numbers so...
2/6 + 2/6 + 1/6 = 5/6
2007-11-14 21:09:15 · answer #4 · answered by jessie's girl 2 · 0⤊ 2⤋
1/6 chance
1, 3, 5 are prime which means there are 3 #s not prime on each die, meaning 6 for the role, out of 36 so 6/36 which is reduced to 1/6
I think
2007-11-14 21:08:59 · answer #5 · answered by ReignInVictory 2 · 0⤊ 1⤋
Damn this is hard sorry i cant help look on the internet to find some sorry
2007-11-14 21:07:35 · answer #6 · answered by Craig B 2 · 0⤊ 2⤋
you are roll
2007-11-14 21:20:40 · answer #7 · answered by danny 1 · 0⤊ 1⤋
1/9th or 11.11%
2007-11-14 21:08:57 · answer #8 · answered by rosenfrozen69 3 · 0⤊ 2⤋