The numbers, 999, 777, and 111 contain a total of nine digits. Cross out one or more of the digits and the sum of the numbers left need to equal eighteen. How would he answer to this puzzle change if directions change to: Cross out one or more of the digits and the sum of the digits left need to equal eighteen. (try to show work) THANK YOU!
2007-11-14 11:57:02 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
are u in ms. embrees class in rancho. im in embree 3rd period.
2007-11-15 12:06:50 · answer #1 · answered by Anonymous · 0⤊ 0⤋
in the first case the sum of 'numbers' suggests that 99+11 would be 110. but in the second case the sum of digits of 99+11 would be 9+9+1+1 = 20
given that idea, in the first case 999, 777, and 111 would have to cross out to __9, __7,1_1, and hopefully the gap between the 1s would allow them to be two separate '
numbers' and so sum to 18. Seems like a stretch though.
and in the second case any 9 7 and any two 1s easily equal 18.
2007-11-14 12:32:18 · answer #2 · answered by Piglet O 6 · 0⤊ 0⤋