hard algebra help?

Question

(2x-3)(3x^2-5x+6)

subtract
2 1/5 - 1 3/4

Answer 1

2 1/5 - 1 3/4

One way you can solve this is to first convert to improper fractions. To convert a mixed fraction into an improper fraction, multiply denominator by whole part, add fractional part.

For 2 1/5: denominator is 5, whole part is 2. 5 times 2 = 10. Add the fractional part 1, to get 10 + 1 = 11. Put over existing denominator, to get

11/5 - 1 3/4

Do the same with 1 3/4

11/5 - 7/4

Now, give them a common denominator. It is necessary to add/subtract fractions. The common denominator is 20. Multiply the top and bottom of the first fraction by 4 ...

44/20 - 7/4

Now, multiply the top and bottom of the second fraction by 5.

44/20 - 35/20

Subtract 44 and 35.

(44 - 35)/20

9/20

Answer 2

(2x - 3)(3x² - 5x + 6)

First multiply 2x times (3x² - 5x + 6)
Then multiply -3 times (3x² - 5x + 6) [be careful to distribute the - sign]
Then combine like terms

2x(3x² - 5x + 6) = 6x³ - 10x² +12x
-3(3x² - 5x + 6) = - 9x² + 15x - 18
6x³ - 10x² +12x - 9x² + 15x - 18
6x³ - 19x² + 27x - 18


2 1/5 - 1 3/4
(get a common denominator)
2 4/20 - 1 15/20
(4/20 is less than 15/20 so you have to borrow)
(Take 1 away from 2 and increase 4 by 20, the value of the denominator)
1 24/20 - 1 15/20
Subtract whole number minus whole number and fraction minus fraction
9/20

Answer 3

(2x-3)(3x^2-5x+6)<-- What is the question?


2 1/5 - 1 3/4 = 11/5 - 7/4 = 44/20 - 35/20 = 9/20

Answer 4

hope i'm not doing your homework for you, haha...
(2x - 3)(3x^2 - 5x + 6) =
6x^3 - 10x^2 + 12x - 9x^2 + 15x - 18 =
6x^3 - 19x^2 + 27x - 18

2 1/5 - 1 3/4 =
11/5 - 7/4 =
44/20 - 35/20 =
9/20