Another AP Calculus Question!!! (and more derivitives)?

Question

1/5(7x+10)^3 + (1-1/x^3)^-1
one fifth(sevenx plus ten)to the third plus (one minus one over x to the third) to the negative 1st.
just in case you didn't get this. =]
thankkks.

Answer 1

1/5(7x+10)^3 + (1-1/x^3)^-1
= 1/5(7x+10)^3 + 1/(1-1/x^3)
dy/dx = (3*7/5)(7x+10)^2 +[x^2*2x -(x^2-1)(2x)]/x^4
dy/dx = 4.2(7x+10)^2 +2(x^2-x^3-2)/x^3