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Calculate the pressure exerted by 0.4962 mol of N2 in a 10.410 L container at 25.0°C. (See Table 5.3.)


Table 5.3
N2 a=1.39 b=.00391

(a) Use the ideal gas law. (Enter your answer for parts a and b using 5 significant figures.)
___atm
(I keep getting this wrong: these are wrong -->1.1162 and 2.3324)

(b) Use the van der Waals equation.
___ atm

2007-11-14 11:21:20 · 1 answers · asked by poo 2 in Science & Mathematics Chemistry

1 answers

I have no idea why you could get 1.1162 and/ or 2.3324.
For ideal gas law, we have: PV = nRT, where P in atm, V in liter, n in mole, T in Kelvin, and R = 0.08206. Put every thing together we get:
P = nRT/V = 0.4962*0.08206*(273.2+25.0)/10.41 = 1.166 (atm).

Please do the same thing on van der Waals equation.

2007-11-17 10:59:48 · answer #1 · answered by Hahaha 7 · 0 0

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