Solve the equation in the interval [0,2pi). tan(x/3) - 1 = 0.?

Question

Please list steps if you can. Thank you.

Answer 1

tan (x/3) - 1 = 0
tan (x/3) = 1
x/3 = pi/4, 5pi/4 <---for x/3 on [0, 2pi)
x = 3pi/4, 15pi/4
x = 3pi/4 <---since 15pi/4 is outside of your interval