2007-11-14 10:46:08 · 6 answers · asked by hamid411200 1 in Science & Mathematics ➔ Mathematics
what are you asking?
2007-11-14 10:49:44 · answer #1 · answered by ElleBObo 3 · 0⤊ 1⤋
I assume you want the factors of these
3x^5 - 3x = 3x(x^4 - 1) = 3x(x^2 + 1)(x + 1)(x - 1)
9x^3 - 9x = 9x(x^2 - 1) = 9x (x + 1)(x - 1)
2007-11-14 18:55:06 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1.3x^5-3x
Factor out any common term. In this case 3x
3x(x^4 - 1)
This is the difference of two perfect squares
3x(x^2+1)(x^2-1)
The second factor is also the difference of two perfect squares.
3x(x^2+1)(x+1)(x-1)
2.
9x^3-9x
Factor out the common term
9x(x^2-1)
9x(x+1)(x-1)
2007-11-14 18:55:08 · answer #3 · answered by Kris S 4 · 0⤊ 0⤋
3x(x^2+1)(x+1)(x-1)
9x(x+1)(x-1)
just to corroborate
2007-11-14 18:52:52 · answer #4 · answered by pickle 2 · 0⤊ 0⤋
3x(x^2+1)(x+1)(x-1)
9x(x+1)(x-1)
2007-11-14 18:50:05 · answer #5 · answered by dunnohow 4 · 0⤊ 0⤋
3x(x^4-1)
3x(x^2-1)(x^2+1)
9x(x^2-1)
9x(x-1)(x+1)
2007-11-14 19:04:15 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋