How much work did the wrestler do on his opponent?
2007-11-14 10:43:56 · 3 answers · asked by navya 1 in Science & Mathematics ➔ Physics
weight= mass * height * gravity
weight= 110kg * 2.8 m * 10Nkg
weight= 3080Nm
2007-11-14 11:35:45 · answer #1 · answered by johnny 3 · 0⤊ 0⤋
Work is force times displacement, making sure the "force in question" is the component of the force in the direction of the displacement. In this case the force is the weight of the 110 kg mass which is 1078 Newtons. Since the lifting force and the displacement are in the same direction the component of the force is the full 1078 N, so the work done is 3,018.4Joules.
2007-11-14 18:50:20 · answer #2 · answered by conradbreen1 1 · 0⤊ 1⤋
Work is the scalar product of force and displacement. The force is mg; the displacement is also given.
W = m g h
2007-11-14 18:48:27 · answer #3 · answered by jgoulden 7 · 0⤊ 1⤋