What must the emf in the figure be in order for the current through the 7.00-ohm resistor to be 1.76A? Each emf source has negligible internal resistance.
Figure: http://i239.photobucket.com/albums/ff92/anakris_24/yf_Figure_26_51.jpg
Appreciate the help :)
2007-11-14 10:33:31 · 3 answers · asked by Hannah 4 in Science & Mathematics ➔ Physics
Let I2 be the current up through the 2-ohm resistor.
Let I3 be the current up through the 3-ohm resistor.
A resulting set of equations is
-(7.00)(1.76) - 2.00 I2 + E = 0
-(7.00)(1.76) - 3.00 I3 + 24.0 = 0
I2 + I3 = 1.76
You now have three linear equations with three unknowns (I2, I3, and E). Solve them using whatever technique you have been taught.
2007-11-14 10:42:33 · answer #1 · answered by jgoulden 7 · 7⤊ 0⤋
Emf Source
2016-10-15 05:49:51 · answer #2 · answered by ? 4 · 0⤊ 0⤋
u actually have to calculate the time constant... time constant is the time required for a capacitor to get 63.5% charged... which is t=r*c simply but for 63.5% mind u.... so u can easily calculate 90% of charge with the relation...
2016-03-13 23:08:28 · answer #3 · answered by Anonymous · 0⤊ 0⤋