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For the resistor network shown in the figure, the ohmmeter reads 20.2ohms. What is the resistance of the resistor X?
Figure: http://i239.photobucket.com/albums/ff92/anakris_24/yf_Figure_26_49.jpg

Thanks for the help :)

2007-11-14 10:31:16 · 2 answers · asked by Hannah 4 in Science & Mathematics Physics

2 answers

The 75.0 and 55.0 resistors are in series.
That sum is in parallel with the 85.
That result is in parallel with the 115.

Now you have a final value in parallel with X. Call it R.
The ohmmeter reading is equal to

R X / ( R + X)

You have R; solve for X.

2007-11-14 10:35:45 · answer #1 · answered by jgoulden 7 · 0 0

Rx = 46.8 ohm.
1/20.2 = 1/Rx + 1/115 + 1/(75+55) + 1/85

2007-11-14 18:39:37 · answer #2 · answered by Luigi 74 7 · 0 0

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