Solve by using systems of equations.
2007-11-14 10:28:32 · 11 answers · asked by sue m 2 in Science & Mathematics ➔ Mathematics
x + y = 28
x - y = 4
Use substitution (or elimination, but I'll use substitution). Solve the second equation for x.
x = 4+y
Plug that in for x in the first equation.
(4+y) + y = 28
4 + 2y = 28
2y = 24
y = 12
Plug this in for y in either equation and solve for x.
x - 12 = 4
x = 16
So your two answers are 12 and 16. Check it.
16 + 12 = 28 Yes
16 - 12 = 4 Yes
2007-11-14 10:38:23 · answer #1 · answered by Deborah P 2 · 0⤊ 0⤋
16 and 12
2007-11-14 10:41:05 · answer #2 · answered by ? 4 · 0⤊ 0⤋
16 and 12
2007-11-14 10:33:26 · answer #3 · answered by Hannah 2 · 0⤊ 0⤋
it is the type you do it. First, upload the numbers. 28+4 = 32. Then, divide the numbers with the aid of 2. 32/2 = sixteen. it is one variety. next, subtract the version from the variety you discovered. sixteen-4 = 12. The numbers are 12 and sixteen.
2016-10-16 13:18:09 · answer #4 · answered by ? 4 · 0⤊ 0⤋
X+Y=28
X-Y=4
add them together
2X=32 therefore X=16
substitute X into any equation
16+Y=28 therefore Y=12
check your answer with the second equation
16-12=4
we are done !
2007-11-14 10:35:22 · answer #5 · answered by David 2 · 0⤊ 0⤋
28 +4= 32-:-2=16 -4=12
so 12 and 16
2007-11-14 10:49:58 · answer #6 · answered by JJ 7 · 0⤊ 0⤋
(28+4)/2 = 16
28-16 = 12
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Ideas to save time: The average of the sum and the difference must be the larger number.
2007-11-14 10:35:53 · answer #7 · answered by sahsjing 7 · 0⤊ 0⤋
Let the no are x & y
so x+y=28------------(1)
& x-y=4--------------(2)
Adding (1) & (2),we get
2x=32 or x =16,putting this value in (1),we get
16+y=28
or y=28-16=12
so 16 & 12 are the ANS
2007-11-14 10:54:25 · answer #8 · answered by MAHAANIM07 4 · 0⤊ 0⤋
12+16= 28
16-12= 4
2007-11-14 10:36:53 · answer #9 · answered by jacket2230 4 · 0⤊ 0⤋
28=16+12
16-12=4 ("Their difference is 4")
2007-11-14 11:45:49 · answer #10 · answered by Daniel 2 · 0⤊ 0⤋