A. 5(x^3)^4 (3x^2)
B. (x^4-4x+3)/ ((√x)+1)
The answer for A. is:
180x^13 + 30x^13
The answer for B. is:
(2√x ((√x)+1)(4x^3-4) - x^4 - 4x+3) / ((2√x)((√x)+1)^2)
I'm not sure how to get the answers! Please help!!
2007-11-14 10:23:15 · 3 answers · asked by NEpatriots12 2 in Science & Mathematics ➔ Mathematics
A.
5(x^3)^4 (3x^2)
= 15x^12 x^2
[15x^12 x^2]'
= 180x^13 + 30x^13
= 210x^13
B.
[(x^4-4x+3)/ ((√x)+1)]'
= [(4x^3-4)(√x+1) - 1/(2√x)(x^4-4x+3)]/((√x)+1)^2
= (2√x ((√x)+1)(4x^3-4) - x^4 - 4x+3) / ((2√x)((√x)+1)^2)
2007-11-14 10:27:37 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋
A as written does not make sense. It cannot give the answer you state. Please check to see if you have stated the problem correctly.
For B, just use the quotient rule. You should get:
(â(x)+1)(4x^3-4) -(x^4-4x+3)(1/(2â(x)))/(â(x)+1)^2
Now you can simplify this a bit.
2007-11-14 18:40:19 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
waa// me no see
2007-11-14 18:25:30 · answer #3 · answered by Eric L 2 · 0⤊ 0⤋