math please help?

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identify common factors and simplify, 1024/288, x:4x^3, and 16x^2y^3:12x^y. i just cant figure these three out please help

2007-11-14 09:28:45 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

1024/288 = 32/9 CF = 32

x:4x^3 = 1/4x^2 CF = x

16x^2y^3:12x^2y = 4y^2/3 CF = 4x^2y
Yo left the exponent out so I assumed it was 2

2007-11-14 09:38:30 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋

1024/288 = 2^10/2*12^2 = 2^9/(2*2*3)^2 = 2^5/3^2

2007-11-14 17:37:06 · answer #2 · answered by Robert S 7 · 0⤊ 0⤋

I have not come to that yet in my math sorry I hope that you figure it out!

2007-11-14 17:36:23 · answer #3 · answered by Anonymous · 0⤊ 0⤋