im making a friendship braclet and idk how long 80" is. i no im an idiot but about how long is it?
2007-11-14 07:59:21 · 12 answers · asked by KCSfieldhockeyy 1 in Beauty & Style ➔ Fashion & Accessories
usually 6" higher than a door frame...
2007-11-14 08:03:09 · answer #1 · answered by "Train" 3 · 0⤊ 0⤋
80" / 12 = 6 ft 8 inches long hmmm right around 2 meters.
same as a tall person, about the same as a couch or sofa. Two real long footsteps plus the length of your foot.
Got a tape measure, yardstick, ruler? Measure it out on the floor or in your yard.
2007-11-14 08:05:49 · answer #2 · answered by don_sv_az 7 · 0⤊ 0⤋
your making a friendship braclet that is 80 inches? are you sure that you are reading the directions right? thats almost 7 feet.
2007-11-14 08:08:11 · answer #3 · answered by Whit 4 · 0⤊ 0⤋
Well, there's 12 inches in a foot (12" in a 1'). So 12" times 6.5"(really is about 6.6 but i'm rounding) is about 80". So it is about 6.5 or 6 1/2 feet long.
2007-11-14 08:07:18 · answer #4 · answered by L.M.L 6 · 0⤊ 0⤋
80" = 80 inches = 6 1/2 feet long
For comparisons, its almost as tall as the door entering your bedroom or kitchen or bathroom. Those are normally 84"
2007-11-14 08:03:25 · answer #5 · answered by teamlessbear 4 · 0⤊ 0⤋
Okay, this has a couple of variables - namely, are you using English Standard or Metric measurements.
If you're using English Standard, then you're talking about 6 feet, 8 inches in length.
If, on the other hand, you're dealing in Centimeters, then you'll want to use 203.2cm (1 inch = 2.54 cm).
2007-11-14 08:17:14 · answer #6 · answered by Anonymous · 0⤊ 0⤋
80 inches is just shy of 7 feet. Think "Michael Jordan" plus 2 inches.
2007-11-14 08:03:37 · answer #7 · answered by unabashed 5 · 0⤊ 0⤋
80" = 6' 8"
2007-11-14 08:03:13 · answer #8 · answered by Jessie H 6 · 0⤊ 0⤋
80" think about it, 72 " is 6 feet....about 6.5 feet...maybe a basketball player?
2007-11-14 08:06:56 · answer #9 · answered by Pika 3 · 0⤊ 0⤋
about as tall as a door way.
2007-11-14 08:06:03 · answer #10 · answered by mtchndjnmtch2000 4 · 0⤊ 0⤋