Can you please help me with this ?

Question

x - y = - 2
2x - y = 5

Answer 1

yes i can!

x - y = -2 (eq.1)
2x - y = 5 (eq.2)


from eq.1 we get the value of x,

x = y - 2

substitute the x in eq.2

2 ( y - 2) - y = 5

simplify the equation,

2y - 4 -y = 5

y = 5 + 4

y = 9
substitute the y in eq 1 or eq 2 to get the value of x.
x - y= -2
x - 9 = -2
x = 9 -2

x = 7

hoer it helps you.

Answer 2

Multiply Eqn. 1 by -1 and add the result to Eqn. 2.....

-x + y = 2
2x - y = 5
-------------
x = 7

Solve for y using rearranged versions of either equation (I'll use the first one for the heck of it):

y = x + 2 = 7 + 2 = 9

Answer 3

Is this a system of equations? Well, anyway if it is here goes:

you have to eliminate one variable first (either one). Lets go with y:

So, to the top equation, multiply by -2 to make the x variable cancellable (is that a word?). You get: -2x + 2y = 4

Now you can cancel the x's and you have that y=9.

Now that you know that, plug it into either equation to get your x value, lets do the top one as it is more simple: x-9 = -2. So you add 9 to both sides, and you get x=7.

You can check if you want: 7-9 = 2? Yes it does. And, 14-9 = 5? That does too.

Answer 4

The intersection points of these straight lines are:
x = 7
y = 9

Answer 5

What do you want to know? The intersection point of these straight lines?

x = 7
y = 9

Answer 6

Who spilled the alphabet in the math again?

Answer 7

x=7**************** x-y=-2
y=9 ********** ****** x=y-2
x-y=-2 ***************** x=9-2
2x-y=5 **************** x=7
2(y-2)-y=5
2y-4-y=5
y-4=5
y=9

Answer 8

4a squared - 6/(b-2) =12.

Does that help?

Answer 9

x=7
y=9
hope that helps

Answer 10

blah