The given function is f(x) = -3x(squared) + 12x + p.
- At which p does point (p, 14) lie on the graph of f?
The subject is quadratic relationships. I know that I either have to use the quadratic formula in some way, but I don't know how, as p is also in the x and y coordinates.
And please, no stupid comments like ' do you homework yourself '. It's study : )
Thanks a lot!
2007-11-14 04:16:17 · 5 answers · asked by pallasfield 2 in Science & Mathematics ➔ Mathematics
p does point (p, 14) lie on the graph of f
=>
f(p)=-3*p^2 +12p+p =14
-3p^2 +13p-14 =0
=>p=2 or p=7/3
2007-11-14 04:24:43 · answer #1 · answered by think_it_over 2 · 1⤊ 0⤋
f(x) = -3x² + 12x + p.
f(p) = 14
14 = -3p² + 12p + p
3p² - 13p + 14 = 0
Now you can use the quadratic formula.
2007-11-14 04:25:54 · answer #2 · answered by DWRead 7 · 0⤊ 0⤋
14= -3p^2+12p+p
3p^2-13p+14 = 0
p = (13 +/- 1)/6 = 2 or 7/3
2007-11-14 04:28:43 · answer #3 · answered by ironduke8159 7 · 0⤊ 1⤋
just look for p when x = p & f(x) = 14! :D
in other words, solve for
14 = -3p^2 +12 p +p
there should be two values :D
2007-11-14 04:26:22 · answer #4 · answered by winnydamarpoe 2 · 0⤊ 0⤋
man asked god,"I want peace",
God said, remove that I as that is Ego,
Remove that 'want' as it is desire,
and "peace" will be all yours.
I tried but get the above solution only
2007-11-14 04:25:13 · answer #5 · answered by krishna 2 · 0⤊ 0⤋