How do i solve the derivative of this function?

Question

f(x)=(x^2+2*x+5)/(x^2-5*x+1)

Answer 1

Use quotient rule:
f '(x) = [(x^2-5*x+1)(2x+2) - (x^2+2*x+5)(2x-5)]/(x^2-5*x+1)^2
Now expand and simplify for final answer

Answer 2

D= denominator
N = Nummerator
Use the quotient rule.
[D ( derivative of N) - N ( derivative of D)] all divided by D^2.
[(x^2-5x+1)(2x+2) - (x^2+2x+5)(2x-5)] / (x^2-5x+1)^2
You can simplify it if you want.

Answer 3

(x^2 + 2x +5) / (x^2 - 5x + 1)

dy/dx = [(2x + 2) / (x^2 - 5x + 1)] - [(2x - 5)(x^2 + 2x + 5) /

(x^2 - 5x + 1)]