A string has a linear density of 6.40 10-3 kg/m and is under a tension of 280 N. The string is 1.9 m long, is fixed at both ends, and is vibrating in the standing wave pattern shown below in the drawing.
(a) Determine the speed of the traveling wave.
m/s
(b) Determine the wavelength of the traveling wave.
m
(c) Determine the frequency of the traveling wave.
Hz
http://img136.imageshack.us/img136/3117/p1729xj0.gif
2007-11-14 02:54:17 · 2 answers · asked by Jeff 4 in Science & Mathematics ➔ Physics
a) speed = sqrt (T / mu)
they give you tension (T) and linear density (mu).
b) You can see from the picture that the wavelength is 2/3 the length of the string.
c) frequency = speed / wavelength
2007-11-14 03:13:44 · answer #1 · answered by Anonymous · 1⤊ 0⤋
a) v=sqrt(Tn/(L/m))
v= sqrt(280/6.40 E-3)=
v=209 m/s
b) For a fundamental harmonic the wavelength
lambda = v/f
From the drawing however you have 1.5 waves in a length L
lambda=L/(3/2)= 2L/3=2x1.9 / 3=1.27m
c) f=v/(lambda)
f=209/1.27=165 Hz
2007-11-14 03:29:52 · answer #2 · answered by Edward 7 · 2⤊ 0⤋